TypeError: `'float' object cannot be interpreted as an integer` (Fix)

Fix the Python error TypeError: 'float' object cannot be interpreted as an integer. This error happens when Python needs a whole number, but your code gives it a float instead.

This page shows what the error means, where beginners usually see it, and the safest ways to fix it.

Quick fix

count = 5.0

for i in range(int(count)):
    print(i)

Output:

Use int() only when converting to a whole number makes sense. If you need decimal values, change the logic instead of forcing a float into range() or another integer-only operation.

What this error means

This error means:

Python expected an integer value
Your code gave a float instead
An integer is a whole number like 3 or 10
A float is a decimal number like 3.5 or 10.0

Even if a float looks like a whole number, such as 5.0, it is still a float type in Python.

If you are not sure about the difference, see Python numbers explained: int, float, complex.

Where beginners usually see this error

Beginners often see this error in places where Python needs a count or a position, such as:

Using range() with a float
Passing a float as a list index
Using a float in string repetition like "a" * 2.5
Using a float where Python needs a count or position

A very common example is the range() function, because range() only accepts integers.

Example that causes the error

Here is a simple example:

for i in range(5.0):
    print(i)

Result:

TypeError: 'float' object cannot be interpreted as an integer

Why this fails:

range(5.0) raises this error
Even 5.0 is still a float, not an int
Python does not automatically treat every float as an integer

Fix 1: Convert the float to int

Use int(value) if a whole number is acceptable.

count = 5.0

for i in range(int(count)):
    print(i)

Output:

This works because int(5.0) becomes 5.

Be careful:

int(value) removes the decimal part
int(5.9) becomes 5, not 6

Example:

value = 5.9
print(int(value))

Output:

If you want to learn more, see Python int() function explained.

Fix 2: Use floor division when creating counts

A common cause of this error is division.

Normal division with / returns a float:

items = 10
count = items / 2

print(count)
print(type(count))

Output:

5.0
<class 'float'>

That can cause a problem here:

items = 10

for i in range(items / 2):
    print(i)

This raises the same error because items / 2 produces a float.

In many counting cases, floor division with // is better:

items = 10

for i in range(items // 2):
    print(i)

Output:

Why this helps:

/ returns a float
// returns a whole-number result in many counting situations
range() needs an integer count

Fix 3: Check earlier math in your code

Sometimes the failing line looks correct, but the variable already became a float earlier.

Example:

total = 12
groups = total / 3

print(groups)
print(type(groups))

for i in range(groups):
    print(i)

Output before the error:

4.0
<class 'float'>

The problem started at this line:

groups = total / 3

A good debugging habit is to print the value and its type before the line that fails.

value = 8 / 2

print(value)
print(type(value))
print(isinstance(value, int))
print(int(value))

Output:

4.0
<class 'float'>
False
4

Useful debugging commands:

print(value)
print(type(value))
print(isinstance(value, int))
print(int(value))

Fix 4: Change the logic if decimals are required

Do not force a float into an integer-only operation if decimals matter.

For example, if you want to step through decimal values, range() is the wrong tool.

This does not work:

for x in range(0.5, 3.0):
    print(x)

Instead, use a while loop and update a float value:

x = 0.5

while x < 3.0:
    print(x)
    x += 0.5

Output:

0.5
1.0
1.5
2.0
2.5

Use this approach when decimal steps are part of the logic.

Beginner debugging steps

If you see this error, follow these steps:

Read the full traceback and find the exact line.
Look for range(), indexing, slicing, or repetition on that line.
Print the variable value.
Print type(variable).
Decide whether to convert the value or rewrite the logic.

Example:

count = 15 / 3

print(count)
print(type(count))

for i in range(count):
    print(i)

After printing the type, you can decide whether:

int(count) is correct, or
count should have been created differently, such as with //

For a broader step-by-step process, see how to debug Python code.

Common mistakes

These are common reasons this error appears:

Using / instead of // before range()
Reading a number from input() and converting it in a way that produces a float
Calculating loop counts with decimal math
Using a float as a list position
Assuming 5.0 is the same as 5 in all Python operations

If you are working with user input, you may also need how to convert string to float in Python.

FAQ

Why does `range(5.0)` fail if `5.0` looks like a whole number?

Because 5.0 is still a float type. range() requires an integer, not a float.

Should I always fix this with `int()`?

No. Use int() only if dropping the decimal part is correct for your program.

What is the difference between `/` and `//` in Python?

/ returns a float. // does floor division and is often better when you need a whole-number count.

Can this error happen outside `range()`?

Yes. It can also happen with indexing, slicing, repetition, and other places that require integer values.

TypeError: 'float' object cannot be interpreted as an integer (Fix)

TypeError: `'float' object cannot be interpreted as an integer` (Fix)